Newton-Kantorovich contraction witness on the closed square s itself
(sup norm), with r = 2^{−s.prec} the half-width and y, z₁, z₂ the exact
dyadic bounds:
0 < normSq c₁ ∧ y + z₁·r + z₂·r²/2 < r ∧ z₁ + z₂·r < 1.
Implies (Mathlib companion): p has exactly one root in the closed square,
it is simple, and it lies in the open square.